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Basile [38]
3 years ago
14

Candice spent 5 1/4 hours doing her homework. Her brother, Ronald, spent 1/2 that number of hours doing his homework. How many h

ours did Ronald spend on his homework?
Mathematics
2 answers:
juin [17]3 years ago
8 0
Ronald spent 2.63 hours doing hw
ELEN [110]3 years ago
6 0

Answer:  Ronald spent 2\dfrac{5}{8} hours on his homework.

Step-by-step explanation: Given that Candice spent 5\dfrac{1}{4} hours doing her homework. Her brother, Ronald, spent half of that number of hours doing his homework.

We are to find the number of hours that Ronald spent on his homework.

Since Ronald spent half of the time as his brother Candice, so the number of hours that Ronald spent on his homework is given by

H_r=\dfrac{1}{2}\times5\dfrac{1}{4}=\dfrac{1}{2}\times\dfrac{21}{4}=\dfrac{21}{8}=2\dfrac{5}{8}.

Thus, Ronald spent 2\dfrac{5}{8} hours on his homework.

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Let's find a.

We are given a right angle which is 90° and an angle marked by "a" next to it. We know that when they are added together, they make a supplementary angle so we can make a equationa and solve.

90 + a = 180

a = 90°

Let's find b.

By looking at the graph, we can tell that the angle "b" and the angle that measures 163° is the same. Thus, b = 163°.

Let's find c.

Using what we did for a, we can solve for c using what we got for b. We can make an equation and solve.

163 + b = 180

c = 27°

Let's find d.

Using the angle that measures 70°, we can solve it like we did with a and c.

70 + d = 180

d = 110°

Let's find e.

Now that we know what d equals, we know that d and e make a supplmentary angle. So, make an equation and solve.

110 + e = 180

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Best of Luck!

5 0
3 years ago
What is the value of Tangent (t/2) if Cosine (t) = 4/5 and t is in quadrant IV?
mihalych1998 [28]

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8 0
3 years ago
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What percent is equivalent to 24/50 24% 48% 50% 52%​
gizmo_the_mogwai [7]

Answer:

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Find the slope of the line that contains (6,-4) and (-4,-4)
frez [133]

Answer:y = -4

Step-by-step explanation: In order to find the slope by these two points, (6,-4), and (-4,-4), you must use the slope formula:

rise/run, which is this case, is y2-y1 / x2 - x1 <--- this is the slope formula

Let 6 be x2, -4 be x1, y2 be -4, and y1 being -4, plug these numbers in.

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0/10 The slope of the line is zero, with a y-axis at -4. We know this because there is a zero in the final result and the y- coordinate between (6,-4) and (-4,-4) do not change in the slightest.

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