<span>The unique things that would separate me from other applicants applying for this job are the ff: (1) i do not care of the compensation but more on the learning i can gather at the end of the day; (2) it has always been my passion to the job; and (3) i want to share my skills and talents to the company as well.</span>
Answer:
h = 28/πr² or 28/(π((14/π)^⅔))
r = (14/π)^⅓
Explanation:
Given
Let r = radius, h = height of the cylinder
Volume, V =28in³
V = πr²h ----- volume of a cylinder
πr²h = 28 --- make h the subject of formula
h = 28/πr²
Area of the the cylinder is;
A = 2πr² + 2πrh
Substitute 28/πr² for h to get area in terms of radius
A = 2πr² + 2πr(28/πr²)
A = 2πr² + 56/r
Differentiate A with respect to r
dA/dr = 4πr - 56/r²
Set dA/dr to 0 (.....using the least amount of metal)
4πr - 56/r² = 0
(4πr³ - 56)/r² = 0 --- Multiply through by r²
4πr³ - 56 = 0
4πr³ = 56 --- make r the subject of formula
r³ =56/4π
r³ = 14/π
r = (14/π)^⅓
h = 28/πr²
h = 28/(π((14/π)^⅔))
