Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
<span>=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) </span>
<span>=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) </span>
<span>=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) </span>
<span>=(r+2)(r+10)/(r-10)</span>
Answer:
<u>A: Congruent</u>
Step-by-step explanation:
The correct answer is <u><em>(2,−1)</em></u>
The population Pa of insect A after t years is given by the equation
Pa = 1.3(1-0.038)^t
while the population Pb of insect B after t years is
Pb = 2.1(1-0.046)^t
We equate the above expressions to find the number of years t it will take the two populations to be equal:
Pa = Pb
1.3(1-0.038)^t = 2.1(1-0.046)^t
1.3(0.962)^t = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.
We can now solve for t:
(0.962)^t / (0.954)^t = 2.1/1.3
(0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
t = log (2.1/1.3) / log (0.962/0.954)
t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
Answer:
It's 1/2 I found this out by subtracting 3/4 - 1/3= 5/12 and if you put that into a decimal it would be .41. So that 1/4= .25 and 1/2= .50. You could figure out that it’s closed to 1/2.
