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Maslowich
3 years ago
5

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 point

s each .a number of beads are then removed from the container. if the product of the point values of the removed beads is 147,000, how many red beads were removed?
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
8 0
Idk this but it might be the points
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Which ordered pair is the best estimate for the solution of the system of equations
Colt1911 [192]

The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)

The given system of equations is:

y=-\frac{1}{2}x + 4.......................(1)\\\\y = \frac{1}{2}x-3..........................(2)

Equate equations (1) and (2)

-\frac{1}{2}x + 4=\frac{1}{2}x -3

Solve for x in the equation above

-\frac{1}{2}x -\frac{1}{2}x =-3-4\\\\-x=-7\\\\x=7

Substitute x = 7 into equation (1)

y=-\frac{1}{2}x + 4\\\\y=-\frac{1}{2}(7) + 4\\\\y=\frac{1}{2}

The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)

Learn more on system of equations here: brainly.com/question/13729904

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2 years ago
Lenny thinks the following expressions are equivalent:
julia-pushkina [17]

Yes, he is correct, using the distributive property you get the same answer

3 0
3 years ago
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What is the difference to the nearest hundredth of a unit between the two zeros
Luda [366]

Answer:

0.1

Step-by-step explanation:

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3 0
3 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
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lozanna [386]

Answer:

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Step-by-step explanation:

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