<h3>
Answer: 280</h3>
Work Shown:
x = number of students in the 6th grade class
30% = 30/100 = 0.30
30% of x = 0.30x this is equal to 84 since "30% of the 6th graders are boys (and there are 84 boys in sixth grade)", so we say 0.30x = 84
Divide both sides by 0.30 to isolate x
0.30x = 84
0.30x/0.30 = 84/0.30
x = 280
So there are 280 students overall in the 6th grade class.
Answer:
The ones 1 1/12, 1/12, 10 1/3, and 1 1/9, all go in the less than 10 1/2. And three numbers marked 10 1/2 go in the greater than 10 1/2
Step-by-step explanation:
Answer:
300 tarts
Step-by-step explanation:
we must solve this equation by going backwards
3/4 of something (as 1/4 was given away) is 150
150 / 3/4 is what you must do
or
150 * 4/3
that is
200
3/5 was sold so 2/5 was left
2/5 of something is 200
200 / 2/5
200 * 5/2
that is
500
3/5 of that was sold
so
500 * 3/5 is 300
300 tarts were sold
Answer:
126
Step-by-step explanation: Add 99+27 to get a total difference of 126.
Answer: The mean difference is between 799586.3 and 803257.9.
Step-by-step explanation: To estimate the mean difference for confidence interval:
Find the statistic sample:
- d = value of 6th - value of 13th;
- Sample mean of difference: mean = ∑d / n
- Sample standard deviation: s = ∑(d - mean)² / n - 1;
For the traffic count, mean = 1835.8 and s = 1382607.3
The confidence interval is 90%, so:
α = 
α = 0.05
The degrees of dreedom are:
df = n - 1
df = 10 - 1
df = 9
Using a t-ditribution table, the t-score for α = 0.05 and df = 9 is: t = 1.833.
Error will be:
E = 
E = 1.833.(
)
E = 801422.1
The interval is: mean - E < μ < E + mean
1835.8 - 801422.1 < μ < 1835.8+801422.1
-799586.3 < μ < 803257.9
The estimate mean difference in trafic count between 6th and 13th using 90% level of confidence is between 799586.3 and 803257.9.