Answer:
The change in the car's distance is 8 feet
Step-by-step explanation:
* Lets explain how to solve the problem
- A car is driving away from a crosswalk
- The distance d (in feet) of the car from the crosswalk t seconds
since the car started moving is given by the formula d = t² + 3.5
- The time increasing from 1 second to 3 seconds
- We need to now the change of the car's distance from the crosswalk
∵ The equation of the distance is d = t² + 3.5
∵ The time is 1 second
∴ d = (1)² + 3.5
∴ d = 1 + 3.5 = 4.5 feet
∵ The time is 3 seconds
∴ d = (3)² + 3.5
∴ d = 9 + 3.5 = 12.5 feet
∵ The change of the distance = d of 3 sec - d of 1 sec
∵ d of 3 sec = 12.5 feet
∵ d of 1 sec = 4.5 feet
∴ The change of the distance = 12.5 - 4.5 = 8 feet
∴ The change in the car's distance is 8 feet
(x,y) -> (-x, y) because the triangle was reflected over the y-axis
Answer:
x=8
Step-by-step explanation:
2(x+4)=4x-8
2x+8=4x-8
2x+8-8=4x-8-8
2x=4x-16
2x-4x=4x-16-4x
-2x=-16
Divide by -2 on both sides
and get... X=8
Answer:
165
Step-by-step explanation:
you just literally add to find the measure of the angle KLN
30+90+45=165
Step-by-step explanation:
y = 0.5x + 4
When y = 2, x = -4. (shown in graph)
When y = 6, x = 4. (shown in graph)
Hence the domain would be -4 <= x <= 4.
