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Leokris [45]
3 years ago
8

An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir

cle that could fit in the square, as shown below. square with perimeter of 40 inches What is the circumference of the copper circle? Use 3.14 to represent π. Question 1 options: 3.14 inches 31.4 inches 15.7 inches 78.5 inches
Mathematics
2 answers:
RSB [31]3 years ago
6 0

Answer:

31.4

Step-by-step explanation:

Each side of the square has a length of 40 × = 10 inches. 4

The perimeter of the square minus the circumference of the circle is 40 − 31.4 = 8.6

The radius of the circle is 10 = 5 inches, so the circumference of the circle is 2

2 × π × 5 = 10 × 3.14 = 31.4 inches.

Nady [450]3 years ago
4 0

Answer:

31.4 inches.

Step-by-step explanation:

The diameter of the circle will be equal to the length of each side of the square which is 40/4 = 10 inches.

Therefore the circumference of the copper circle

= 3.14 * the diameter

= 3.14 * 10

= 31.4 inches.

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The area of a rectangular-shaped garden can be no more than 64 square feet. If the length of the garden is 16 feet, what could b
Klio2033 [76]

Answer:

4 square feet

Step-by-step explanation:

Area = Length * Width

64 = 16 * W.

W = 4.

So, 4 square feet.

Mark me as Brainliest if this is correct! I really appreciate it! :D

8 0
3 years ago
A city has 7204 recycle bins. The city gives half of the recycle bins to it's citizens. The rest of the recycle bins are divided
Tju [1.3M]
The number of recycle bins that the city gives to citizens:
7204 : 2= 3602
The number of recycle bins is left:
7204 - 3602= 3602
The largest number of bins that can be given in each group:
3602 : 23 = 156 (residual: 14)
=> There are 14 bins left over.
4 0
3 years ago
X+2y=3 <br> 3y+5y=7 <br> I dont know
Lena [83]

Answer:

Step-by-step explanation:

3y+5y=8y

8y=7(divide 8 in both sides to get y)

y=7/8

x+2y=3...but we already know the value of y, so substitute 7/8 to y

x+2(7/8)=3

x+14/8=3

x=3-14/8

=1.25

8 0
3 years ago
A sequence is defined by f(0) = -20, f(n) = f(n-1) - 5 forn &gt; 1.
bulgar [2K]

Answer:

1. Proved down

2. proved down

3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5

Step-by-step explanation:

Let us explain how to solve the question

∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1

→ That means we have an arithmetic sequence with constant

   difference -5 and first term -20

1. → f(1) means we need to find the second term, which equal the

      term - 5

∵ f(1) means n = 1

∴ f(1) = f(1 - 1) - 5

∴ f(1) = f(0) - 5

∵ f(0) = -20

∴ f(1) = -20 - 5 → Proved

2. → f(3) means we need to find the third term, which equal the

   second term - 5

∵ f(3) means n = 3

∴ f(3) = f(3 - 1) - 5

∴ f(3) = f(2) - 5

→ f(2) = f(1) - 5

∵ f(1) = -20 - 5

∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5

∴ f(3) = [-20 - 5 - 5] - 5

∴ f(3) = -20 - 5 - 5 - 5 → Proved

3. → From 1 and 2 we notice that the number of -5 is equal to n,

      at n = 1 there is one (-5), when n= 3 there are three (-5)

∵ n = 10

∴ There are ten (-5)

∴ f(10) = -20 - 5(10)

∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved

6 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
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