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IrinaVladis [17]
3 years ago
15

Math question. I'll give brainliest...

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0
(x^2 + 4)(x^2 - 1) is the answer. Just factor it like a normal binomial.
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Someone can help me with this please​
Marina CMI [18]

Answer:

x = -1 and x = 7

Step-by-step explanation:

2x^2 + 2x - 14x - 14

2x^2 - 12x -14

Divide through by 2 to simplify the expression

x^2 - 6x - 7

x^2 - 6x -7

Now, let's think of two numbers that when added up gives -6 and when multiplied gives -7

Yes! It's -7 and +1

-7 + 1 = -6 , and -7* 1 = -7

Now, lets substitute these numbers in the expression

x^2 -7x + x - 7

factorize

x(x - 7) + 1(x - 7)

(x + 1) (x - 7)

Now equate to zero

(x + 1) (x - 7) = 0

x + 1 = 0

subtract 1 from both sides

x +1 - 1 = 0 -1

x = -1

Also,

x - 7 = 0

Add 7 to both sides

x -7 + 7 = 0 + 7

x = 7

Hence, x = -1 and x =7

6 0
3 years ago
Plzzzz help asap lost ten u gain it asap
faltersainse [42]
Your unit cost will be $0.11 :) 
7 0
3 years ago
Amanda is 12 years old she has two sevens time as old as her father how many years ago was her father four times as old as Amand
Allisa [31]
Ok so first I am assuming you ment 2 sevenths so 12 divided by 2 sevenths is 42. so the father is currently 42. so when she was 10 he was 40. since 10 is 4 times 40 that is the age we need. so 42 minus 40 is 2. therefore the answer is 2.
8 0
3 years ago
Pls help!!
Licemer1 [7]
Answer will be A, and if you need help with math work Connects is a great app to use
8 0
3 years ago
One number is 6 more than another. Twice the larger number is 5 times the smaller.
tresset_1 [31]

Answer:

The smaller number is 4

Step-by-step explanation:

Larger number = x

Smaller number = y

Write 2 equations

y + 6 = x

2x = 5y

Substitute x in the first equation to the second equation

2(y + 6) = 5y

Multiply 2(y + 6)

2y + 12 = 5y

Subtract 2y from both sides of the equation

12 = 3y

Divide both sides of the equation by 3

y = 4

x = y + 6 = 4 + 6 = 10

The smaller number is 4

Hope this helps :)

3 0
3 years ago
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