Math question. I'll give brainliest...

The diameter of Mercury is approximately 4.9×10^3 kilometers. The diameter of Earth is approximately 1.3×10^4 kilometers. About

JulijaS [17]

$\text {Number of times = } \dfrac{1.3 \times 10^4}{4.9 \times 10^3 }$

$\text {Number of times = } \dfrac{1.3}{4.9} \times 10^{4-3}$

$\text {Number of times = } 0.27 \times 10$

$\text {Number of times = } 2.7$

5 0

3 years ago

There are 9 people going on a trip. They purchased coach tickets for $160, and first class tickets for $1180. The total budget t

Savatey [412]

Answer:

Step-by-step explanation:

Given

There are 9 people going on a trip

They purchased coach tickets =$160

first class tickets =$1180

total budget to spend = $4500

Let coach tickets=X

So first class tickets=9-x

160x+1180(9-x)=4500

160+10620-1180x=4500

160x-1180x=4500-10620

-1020x=-6120

X=6120/1020

X=6

So answer

Coach tickets=X=6

First class tickets=(9-x)

=3.

4 0

3 years ago

A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a

zaharov [31]

Answer:

a) $P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)$

And we can find this probability using the complement rule:

$P(z>-1.25)=1-P(z$

b) $P(X$

And we can find this probability uing the normal standard table:

$P(z$

c) $P(3.5$

And we can find this probability with this difference:

$P(-1.25$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.25$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(5,1.2)$