6n=11c=-8j+5
Just combine the terms!
For part (a), first consider the simple case where we roll two dice.What is the probability that the second roll is greater than the first? Assuming a six-sided dice, the total number of outcomes $(i,j)$ is $6^2$.
Answer:
Area of the shaded portion = (120π + 36√3)sq. m
Step-by-step explanation:
Area of the shaded region = Area of circle - Area of triangle
Given
radius of the circle = 12m
Area of the circle = πr²
Area of the circle = π(12)²
Area of the circle = 144π m²
Area of the sector = theta/360 * πr²
Area of the sector = 60/360 * 12²π
Area of the sector = 60/360 * 144π = 24π
Area of the triangle = 1/2 bh
Area of the triangle = 1/2 (12cos30)(12)
Area of the triangle = 36√3
Area of the shaded portion = (144π - 24π + 36√3)sq. m
Area of the shaded portion = (120π + 36√3)sq. m
3.007 ounces per square meter