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NNADVOKAT [17]
3 years ago
14

What is the area of the shaded region in the given circle in terms of pi and in simplest form?

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

Area of the shaded portion = (120π + 36√3)sq. m

Step-by-step explanation:

Area of the shaded region = Area of circle - Area of triangle

Given

radius of the circle = 12m

Area of the circle = πr²

Area of the circle  = π(12)²

Area of the circle  = 144π m²

Area of the sector = theta/360 * πr²

Area of the sector =  60/360 * 12²π

Area of the sector = 60/360 * 144π  = 24π

Area of the triangle = 1/2 bh

Area of the triangle = 1/2 (12cos30)(12)

Area of the triangle = 36√3

Area of the shaded portion = (144π - 24π + 36√3)sq. m

Area of the shaded portion = (120π + 36√3)sq. m

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Answer:

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Step-by-step explanation:

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A motorboat travels 168 kilometers in 4 hours going upstream. It travels 280 kilometers going downstream in the same amount of t
Grace [21]

Answer:

The speed of the boat is 56 km/hr

The rate of the current is 14 km/hr

Step-by-step explanation:

We are given the following;

  • Distance traveled upstream = 168 km
  • Time taken to travel upstream = 4 hours
  • Distance traveled down stream = 280 km
  • Time taken down stream = 4 hours

We are required to determine the speed of the boat in still water and the speed of the current.

We are going to take;

Speed of the boat as = x km/hr

Rate of flow of current = y km/hr

We can determine the speed of the boat upstream;

Speed = Distance ÷ time

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But, the speed upstream is given by (x - y) km/hr

Therefore; ( x-y) km/hr = 42 km/hr ......................... Eqn 1

Speed of the boat down stream

    speed = 280 km ÷ 4 hours

                = 70 km/hr

But, the speed downstream is given by (x+y) km/hr

Therefore, x+y km/hr = 70 km/hr ........................... Eqn 2

Solving Eqn 1 and Eqn 2 simultaneously;

x - y = 42

x + y = 70

Eliminating x

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    y = 14 km/hr

Solving for x,

x = 42 + y

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Therefore, the speed of the boat is 56 km/hr while the rate of the current is 14 km/hr

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