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2 years ago

What is 4/7 of 49 Please explain why

Mathematics

2 answers:

Dovator [93]2 years ago

7 0

28 because if you divide 49 by 7 you would get 7 and then multiply it by 4. Then you get the answer of 28.

Mademuasel [1]2 years ago

6 0

4/7 of 49 = 28, the reason why is because if you divide 49 into 7 different groups, you will get 7 groups of 7(7x7=49). And if you take 4 of those groups, the answer is 28(7x4=28)

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A 10-foot ladder is leaning against a wall. The base of the ladder is 2 feet from the base of the building. How far up the build

Svetlanka [38]

We can see on this graph that the triangle has legs of x and 6 with a hypotenuse of 10 and we can use Pythagoreans theorem to find the unknown side.
Pythagoreans theorem: a^2+b^2=c^2, where a and b are the legs of the triangle and c, is the hypotenuse

x^2+6^2=10^2 Plugin a=x, b=6, and c=10. Now let us solve for x

x^2+36=100 Square each individual term

x^2+=100+36 Subtract 36 from both sides

x^2=64 Combine like terms

sqrt(2)=sqrt(64) Take the square root of both sides

x = 8 Simplify the square root

So our answer is x = 8
The ladder touches the 8 feet mark on the wall.

5 0

2 years ago

what is an equation for the line that passes through the points (0,-4) (7,11) in slope-intercept form

fomenos

Answer:

y=15/7x-4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(11-(-4))/(7-0)

m=(11+4)/7

m=15/7

y-y1=m(x-x1)

y-(-4)=15/7(x-0)

y+4=15/7(x)

y+4=15/7x

y=15/7x-4

4 0

2 years ago

A football is kicked vertically upward from a height of 2 feet with an initial speed of 50 feet per second. The formula h=2+50t-

Oksanka [162]

Answer: 38 feet.

Step-by-step explanation:

The equation of motion of a body thrown vertically upwards:

$\displaystyle\\\boxed {h=h_0+v_0t-\frac{gt^2}{2} \ \ \ \ \ (1)}$ ,

$h_0=2 \ feet\ \ \ \ v_0=50\ feet\ per\ second.$

Substitute in formula (1) the value t=2 c:

$h=2+50*2-16*2^2\\h=2+100-16*2*2\\h=102-64\\h=38\ feet.$

5 0

1 year ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

9 months ago

6.find zeroes by factorisation<br><br>4x2 + 5√2 x - 3

dangina [55]

-13.213203440000000000000

7 0

3 years ago