To solve the question we need to calculate the equation of the straight line;
the equation is given by:
m=(y1-y)/(x2-x)
where;
m is the slope;
selecting 2 points from the graph say (0,2) and (2,0), the slope of the graoh will be:
m=(0-2)/(2-0)=-1
thus using point (-2,4) the equation will be given by:
-1=(y-4)/(x+2)
-1(x+2)=(y-4)
this can be written as:
-x-2=y-4
this can be written as:
y+2=-x+4
this can be written as:
y+2=-(x-2)
The answer is A.y+2=-(x-2)
Answer:
Step-by-step explanation:
Welllllll.....
If you take the square root of 9, it's 3
if you take the square root if 16, it's 4
I would guess it to be about 3.2
Answer:
x+6
Step-by-step explanation:
Answer:
d =
or d = 5.1
Step-by-step explanation:
![d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-1-(-2))^2}\\d= \sqrt{(-5)^2+(1)^2}\\d= \sqrt{25+1}\\d= \sqrt{26}](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%5C%5Cd%3D%20%5Csqrt%7B%28-5-0%29%5E2%2B%28-1-%28-2%29%29%5E2%7D%5C%5Cd%3D%20%5Csqrt%7B%28-5%29%5E2%2B%281%29%5E2%7D%5C%5Cd%3D%20%5Csqrt%7B25%2B1%7D%5C%5Cd%3D%20%5Csqrt%7B26%7D)