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3 years ago

Solve x2 - 8x + 14 = 6 - 2x x = or x =

Mathematics

2 answers:

Serhud [2]3 years ago

6 0

Answer:

x = 4 and x = 2

Step-by-step explanation:

If this is the equation you're looking for: x^2 - 8x + 14 = 6 - 2x then here:

x^2 - 8x + 14 = 6 - 2x

x^2 +14 = 6 +6x

x^2 +8 = 6x

x^2 = 6x - 8

√x^2 = √6x - 8

x = 4 and x = 2

nikdorinn [45]3 years ago

3 0

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x
=
4
,
2

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A company makes and sells charm bracelets. The cost of producing x bracelets is represented by the function C(x) = 180 + 8x. The

alexdok [17]

Answer:

The correct answer would be, No of bracelets the company must sell to break even would be 15

Step-by-step explanation:

Revenue is given by the function as:

R(x) = 20x

and Cost is given by the function as:

C(x) = 180 + 8x

Let the function P(x) represent the profit earned.

We know that Profit is equal to Revenue - Cost

i-e

Profit = Revenue - Cost

So,

P(x) = R(x) - C(x)

Now substituting the Revenue and cost values in the above equation.

P(x) = 20x - (180 + 8x)

P(x) = 20x -180 -8x

P(x) = 20x - 8x -180

P(x) = 12x - 180

Now if we want to find out the break even point, we would consider profit as Zero, 0. So substituting 0 in the above equation for Profit, we will get:

0 = 12x - 180

12x = 180

x = 180/12

x = 15

So the break even point will be 15 bracelets.

8 0

3 years ago

Convert,the complex number into polar form: 4+4i

kow [346]

Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656

$cos\theta = \frac{a}{r}$
$cos\theta = \frac{4}{4\sqrt{2}}$
$cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$cos\theta = \frac{4\sqrt{2}}{4(2)}$
$cos\theta = \frac{4\sqrt{2}}{8}$
$cos\theta = \frac{\sqrt{2}}{2}$
$2(cos\theta) = 2(\frac{\sqrt{2}}{2})$
$2cos\theta = \sqrt{2}$
$2cos\theta = 1.414$

$sin\theta = \frac{b}{r}$
$sin\theta = \frac{4}{4\sqrt{2}}$
$sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$sin\theta = \frac{4\sqrt{2}}{4(2)}$
$sin\theta = \frac{4\sqrt{2}}{8}$
$sin\theta = \frac{\sqrt{2}}{2}$
$2(sin\theta) = 2(\frac{\sqrt{2}}{2})$
$2sin\theta = \sqrt{2}$
$2sin\theta = 1.414$

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

$\theta = tan^{-1}\frac{b}{a}$
$\theta = tan^{-1}\frac{4}{4}$
$\theta = tan^{-1}(1)$
$\theta = 45$

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).

5 0

3 years ago

A school has 18 classes with 35 students in each class. In order to reduce class size to 30,how many new classes have to be form

Mekhanik [1.2K]

1 class with 5 student

5 0

3 years ago

Read 2 more answers

I need help

Evgesh-ka [11]

Answer:

your

Step-by-step explanation:

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DELETED :)

Enjoy the rest of your day lovebug, if helpful... dont hesitate to mark as brainliest! ;)

5 0

3 years ago

Write a linear function F with the values F(-9)=8 and F (0) =1

Fiesta28 [93]

Given:

The values of a linear function are $F(-9)=8$ and $F(0)=1$ .

To find:

The linear function.

Solution:

If a linear function passes through two points, then the equation of the linear function is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The values of a linear function are $F(-9)=8$ and $F(0)=1$ . It means the function passes through the points (-9,8) and (0,1). So, the equation of the linear function is:

$y-8=\dfrac{1-8}{0-(-9)}(x-(-9))$