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zavuch27 [327]
4 years ago
14

A bank teller notices that an account was overdrawn and had a balance that can be represented by –$324. The account holder then

deposited 3 checks for $150 each and made 4 withdrawals of $20 each. The teller used the steps below to find the new balance for the account. Step 1 Start: –$324 Deposits: $150 each Withdrawals: –$20 each Step 2 –324 + 3(150) + 4(–20) Step 3 –324 + 450 – 80 = 46 Step 4 The account is overdrawn by $46.
Mathematics
2 answers:
Dmitry [639]4 years ago
5 0

Answer:

it would not be overdrawn because it would be money he can spend not in the hole.

Step-by-step explanation:

Wittaler [7]4 years ago
4 0

Answer:

Step-by-step explanation:

-324+3*150 = 126

126- 4 * 20 = 46

no. the account has 46 left. not overdrawn

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One bag of rice that weighs 4.5 pounds will have enough rice if a recipe calls for 60 ounces of rice. (1 pound = 16 ounces)
dimulka [17.4K]

Answer:

Step-by-step explanation:

Since the bag of rice is 4.5 pounds, and there are 16 ounces per pound, multiply 16 x 4 = 64. Now what is half of 16? 8! So divide 5/8 = 0.625.

So in the end, yes the bag of rice will have enough rice. Here's my math:

16 x 4 = 64

5 / 8 = 0.625

So, you will have 64.625 ounces of rice which is plenty for your recipe!

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I really hope this helps you!

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Answer:

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4 years ago
Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
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