(E) ionic aluminum fluoride (AlF3)
Answer:
0.4 moles of water produced by 6.25 g of oxygen.
Explanation:
Given data:
Mass of oxygen = 6.25 g
Moles of water produced = ?
Solution:
Chemical equation;
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 6.35 g/ 32 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of oxygen with water:
O₂ : H₂O
1 : 2
0.2 : 2×0.2 = 0.4 mol
0.4 moles of water produced by 6.25 g of oxygen.
Answer:
[H₃O⁺] = 6.31 x 10⁻³ M.
Explanation:
- To find the hydronium ion concentration [H₃O⁺], we can use the relation:
<em>pH = - log[H₃O⁺].</em>
<em></em>
∴ 2.2 = - log[H₃O⁺].
∴ log[H₃O⁺] = - 2.2
<em>∴ [H₃O⁺] = 6.31 x 10⁻³ M.</em>