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Amanda [17]
3 years ago
9

What formula can be used to calculate [H30+]

Chemistry
1 answer:
Yuliya22 [10]3 years ago
4 0
[H3O+] is just the same with [H+]. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14
Read more on Brainly.com - brainly.com/question/1365379#readmore
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Write the balanced equation and draw the particulate representation of the following chemical reaction: sodium metal reacts with
KonstantinChe [14]

Answer:

2Na + Cl2 ------> 2NaCl

4H2O2 --------> 4H2O + 2O2

CH4 + 2O2 -------> CO2 + 2H2O

Explanation:

5 0
3 years ago
What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?
NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

RMS=\sqrt{\frac{3RT}{M} }; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

V1 for 238 UF_{6}; M1=238+114=352g/mole

V1 for 235 UF_{6}; M1=238+114=352g/mole

V1=\sqrt{\frac{3RT}{352} };

V2=\sqrt{\frac{3RT}{349} };

\frac{V1}{V2}=ratio of 238UF_{6} F6 to 235UF_{6}=\sqrt{\frac{349}{352} };

\frac{V1}{V2} =0.9957m/s;

\frac{V1}{V2} =0.996m/s;

4 0
3 years ago
What are two good conductors
Mekhanik [1.2K]
Water and copper hope this helps:)
8 0
3 years ago
Read 2 more answers
What kind of phase transition will occur when energy is continuously supplied to a solid sample?
Annette [7]
The correct answer should be C. Melting because if energy such as thermal energy is supplied to a solid such as ice then it would melt
5 0
3 years ago
Read 2 more answers
) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that t
sergeinik [125]

Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

m_{calcite}=15.4448g-12.4631g=2.9817g

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL

Thus, the density of the calcite sample will be:

\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

Learn more:

  • brainly.com/question/12001845
  • brainly.com/question/11242138

Regards!

6 0
2 years ago
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