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3 years ago

What formula can be used to calculate [H30+]

1 answer:

4 0

[H3O+] is just the same with [H+]. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14
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Write the balanced equation and draw the particulate representation of the following chemical reaction: sodium metal reacts with

KonstantinChe [14]

Answer:

2Na + Cl2 ------> 2NaCl

4H2O2 --------> 4H2O + 2O2

CH4 + 2O2 -------> CO2 + 2H2O

Explanation:

5 0

3 years ago

What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?

NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

$RMS=\sqrt{\frac{3RT}{M} }$ ; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

$V1 for 238 UF_{6}; M1=238+114=352g/mole$

$V1 for 235 UF_{6}; M1=238+114=352g/mole$

$V1=\sqrt{\frac{3RT}{352} }$ ;

$V2=\sqrt{\frac{3RT}{349} }$ ;

$\frac{V1}{V2}$ =ratio of $238UF_{6} F6 to 235UF_{6}$ = $\sqrt{\frac{349}{352} }$ ;

$\frac{V1}{V2} =0.9957m/s;$

$\frac{V1}{V2} =0.996m/s;$

4 0

3 years ago

What are two good conductors

Mekhanik [1.2K]

Water and copper hope this helps:)

8 0

3 years ago

Read 2 more answers

What kind of phase transition will occur when energy is continuously supplied to a solid sample?

Annette [7]

The correct answer should be C. Melting because if energy such as thermal energy is supplied to a solid such as ice then it would melt

5 0

3 years ago

Read 2 more answers

) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that t

sergeinik [125]

Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

$m_{calcite}=15.4448g-12.4631g=2.9817g$

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

$V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL$

Thus, the density of the calcite sample will be:

$\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL$

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

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Regards!

6 0

2 years ago