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3 years ago

Why are properties of covalent compounds so diverse

Chemistry

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

The diversity of physical properties among covalent compounds is mainly because of widely varying intermolecular attractions. ... All of the atoms are covalently bonded to each other.

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Nearly_____of the Earth is covered by water.

mario62 [17]

Answer:

im sure its 71%

Explanation:

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4 years ago

Read 2 more answers

Help plz:)))I’ll mark u Brainliest

Wittaler [7]

Answer:

2.475 mol of O2 formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of O2 = 1.65 mol KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of O2 formed = 2.475 mol of O2

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3 years ago

Below are two cell division diagram. the number represents the number of chromosomes inside the cell. write the type of cell div

zheka24 [161]

Answer:

The cell division in which number of chromosome remain same is mitosis and in it is reduced to half is mieosis.

Explanation:

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3 years ago

Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to

vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

$H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)$

Next we will calculate how many moles of $H_2SO_4$ are present in 85.00 mL of 1.500 M sulfuric acid.

As, Molarity = $\frac{\text{moles of solute}}{\text{liters of solution
}}$

1.500 M = $\frac{n}{0.08500 L
}$

n = 0.1275 mol $H_2SO_4$

Now set up and solve a stoichiometric conversion from moles of $H_2SO_4$ to grams of $NaHCO_3$ . As, the molar mass of $NaHCO_3$ is 84.01 g/mol.

$0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})$

= 21.42 g $NaHCO_3$

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

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3 years ago

MINUTES 15-20 IN THE VIDEO

STALIN [3.7K]

Answer:

NBPI NMB 4567IY3ERV-90668%^

Explanation:

NJOJFDSSEDFGHJMKNHBGVCDS4DR6TYUJN

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3 years ago