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Arte-miy333 [17]
3 years ago
8

Please help is it greater than or less than7*3_9*2​

Mathematics
1 answer:
mezya [45]3 years ago
6 0
The answer is >,, 21>18
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How to solve for x where (2^x)*x =n?
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3 years ago
N-4n=-9+6n<br> A) (-9)<br> B) (1)<br> C) (All real numbers. }<br> D) (14)
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6 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
The table above lists the frequencies of the C major key.
Talja [164]
Sj ebfbruejnxjjendnzjejnzzkijeskao
7 0
3 years ago
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