All categories

3 years ago

2:5 is how much out of 27

Mathematics

1 answer:

spayn [35]3 years ago

5 0

13.5 is your answer, here u are

You might be interested in

a) On Wednesday, Harry sold 3 times as many candy bars as on Tuesday. On Thursday, he sold 5 times as many bars as on Wednesday.

Alborosie

Answer:

Tues=8 Weds=24 Thurs=120

Step-by-step explanation:

The question can be modeled by the equation x+3x+15x=152

x is the amount sold on tuesday, 3x is 3 times the amount sold on tuesday so it represents wednesday and 15x represents thursday as it is 5 times the amount sold on wednesday.

Now we just need to solve for x to figure out how many he sold each day.

x+3x+15x=19x

19x=152

x=152/19

x=8

To find the amount sold on each day just mulitiply x by the coefficient

Tuesday = x = 8

Wednesday = 3x = 3*8 = 24

Thursday = 15x = 15*8 = 120

4 0

3 years ago

Someone please help me with this one

Anna35 [415]

Answer:

k=-2x+9

Step-by-step explanation:

-4x+6=k*2x-3

+3 +3

-4x+9=k*2x

/2x /2x

-2x+9=k

8 0

4 years ago

Help math 50 points!!!!!!!!!!!!

morpeh [17]

A. Hope I helped.......

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

What is the y-intercept in the equation y=8x+6

lisabon 2012 [21]

Answer:

(0,6) or 6

Step-by-step explanation:

To find the y-intercept look at the last variable you have, which in this case is 6. Glad to help :)

7 0

3 years ago