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VladimirAG [237]
2 years ago
8

Plz help me with this problem

Mathematics
1 answer:
Evgen [1.6K]2 years ago
3 0
First we rearrange by using the definition of between.
AB=x+10, BC=x+14, AC=22
Given that AB+BC=AC, we can solve for X
(X+10)+(X+14)=22
X+10+X+14=22
2X+24=22
2X+24-24=22-24
2X=-2
2X/2=-2/2
X= -1
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Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

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For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

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Step-by-step explanation:

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