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3 years ago

Form the intersection for the following sets.

Mathematics

1 answer:

Dafna11 [192]3 years ago

7 0

The intersection of two sets is the set composed by the elements that the two sets have in common.

So, we have

$X\cap Y = \{100,\ 1000\}$

In this particular case, since Y is a subset of X, we have

$X\cap Y=Y$

In fact, all elements of Y are elements of X as well, so in particular they are common elements.

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Find the perimeter of a<br> rectangle with length 6 units<br> and width 4 units.<br> wa

agasfer [191]

Answer:

The perimeter of the given rectangle = 20 units.

Step-by-step explanation:

Length of the rectangle = 6 units

The width of the rectangle = 4 units

Now Perimeter of the Rectangle = 2 ( LENGTH + WIDTH)

⇒Here, perimeter = 2 ( 6 units + 4 units ) = 2 x ( 10 units)

= 20 units

Hence, the perimeter of the given rectangle = 20 units.

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3 years ago

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denpristay [2]

Answer:

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Step-by-step explanation:

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2 years ago

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dmitriy555 [2]

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3 years ago

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TiliK225 [7]

Answer:

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3 years ago

According to the fundamental Theorem of algebra, which polynomial function has exactly 11 roots?

liraira [26]

<h2>Explanation:</h2><h2></h2>

The Fundamental Theorem of Algebra states the following:

<em>For</em><em> </em><em>any polynomial of degree n we will have n roots.</em>

<em />

So the general form of the equation of a polynomial is:

$A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq$

Since our polynomial will have exactly 11 roots, then the equation will have the following form:

$f(x)=a_{11}x^{11}+a_{10}x^{10}+\ldots +a_{2}x^{2}+a_{1}x+a_{0}$

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3 years ago