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Tanzania [10]
3 years ago
10

How to change a number ten by rounding

Mathematics
2 answers:
klio [65]3 years ago
7 0
Can change no 10 and 10 is rounded no
Llana [10]3 years ago
4 0
10 is already rounded
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You're given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side
igomit [66]

Answer: To find the third side of a triangle (there are two answers you could get), you need to use the Pythagorean formula: a^2+b^2=c^2.  First answer, 3^2+5^2=c^2.  Solve for c.  c=5.83.  The second answer, 3^2+b^2=5^2.  Solve for b.  b=4.

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5 0
2 years ago
jan has a 12-ounce milkshake.Four ounces in the milkshake are vanilla,and the rest is chocolate.What are two equivalent fraction
bagirrra123 [75]

Answer:

In this item, we are given that out of 12 ounces of ingredients comprising the milkshake, there are 4 ounces vanilla. Expressing this into fraction will give us an answer of 4/12. This fraction can be one of the answers. Since we are asked for two fractions, we can simplify 4/12 such that we get an equivalent fraction that is equal to 2/6. Hence, the answers to this question are 4/12 and 2/6.

Step-by-step explanation:

7 0
2 years ago
Find the greatest common factor of 10, 30,10,30,10, comma, 30, comma and 454545.
borishaifa [10]

Answer:

GCF = 5

Step-by-step explanation:

Given:

The numbers are given as:

10, 30 and 45

A factor of a number is a number by which the given number is evenly divisible.

Example: 2 is a factor of 4 as 4\div 2 =2. So, 4 is evenly divisible by 2 and hence 2 is a factor of 4.

Now, factors of 10 = 1, 2, <u>5</u>, 10.

Factors of 30 = 1, 2, 3, <u>5</u>, 6, 10, 15, 30.

Factors of 45 = 1, 3, <u>5</u>, 9, 15, 45.

So, the greatest common factor in all the three numbers is 5.

Hence, the greatest common factor of 10, 30 and 45 is 5.

5 0
3 years ago
El Sr negron tiene que redactar una serie de cartas en su oficina. A Lourdes le toma 6 horas pasar todas las cartas. A su compañ
vodka [1.7K]

El Sr negron tiene que redactar una serie de cartas en su oficina. A Lourdes le toma 6 horas pasar todas las cartas. A su compañera rosabel, le toma 9 horas en realizar la misma tarea. Si ambas trabajan juntas para hacer todo el trabajo d ela oficina,

a. Cuánto tiempo le tomará a ambas realizar el trabajo?

Answer:

3.6 horas

Step-by-step explanation:

Sea el número total de horas que ambos trabajaron = T

Deje que la cantidad total de letras por las que pasaron = 1

De la pregunta, se nos dice:

Lourdes necesitó 6 horas para revisar las cartas.

Esto significa que, cada 1 hora, Lourdes revisaba 1/6 de las letras

Rosabel tardó 9 horas en leer las letras.

Esto significa que, cada 1 hora, Rosabel revisó 1/9 de las letras

Por lo tanto,

(1/6 × 1) T + (1/9 × 1) T = 1

(1/6 + 1/9) T = 1

(3 + 2/18) T = 1

(18/5) T = 1

5T / 18 = 1

Cruz multiplicar

5T = 18

T = 18/5

T = 3.6 horas

Por lo tanto, les tomó a ambas 3.6 horas hacer el trabajo.

7 0
3 years ago
PLSS HELP!! VERY EASY.
gogolik [260]

Answer:

35 ways

Step-by-step explanation:

Alex has 9 friends and wants to invite 5 friends. Since Alex requires two of his friends who are twins to come together to his birthday party, since the two of them form a group, the number of ways we can select the two of them to form a group of two is ²C₂ = 1 way.

Since we have removed two out of the nine friends, we are left with 7 friends. Also, two friends are already selected, so we are left with space for 3 friends. So, the number of ways we can select a group of 3 friends out of 7 is ⁷C₃ = 7 × 6 × 5/3! = 35 ways.

So, the total number ways we can select 5 friend out of 9 to  party come to the birthday include two friends is  ²C₂ × ⁷C₃ = 1 × 35 = 35 ways

3 0
3 years ago
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