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Delvig [45]
3 years ago
8

Find the equation of the line through point (-2,8) with slope 1/2.

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

you gotta show us the graph

Step-by-step explanation:

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Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of
White raven [17]

Answer:

2/3

Step-by-step explanation: parallel lines have the same slope with different y-int

7 0
3 years ago
Need help please this question is very confusing i would love some help
Natali [406]

Answer:

D

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (- 3, - 6), thus

y = a(x + 3)² - 6

To find a substitute (0, 0) into the equation

0 = 9a - 6 ⇒ a = \frac{6}{9} = \frac{2}{3}

y = \frac{2}{3}(x + 3)² - 6 ← in vertex form

Expand (x + 3)² and distribute by \frac{2}{3}

y = \frac{2}{3}(x² + 6x + 9) - 6

  = \frac{2}{3} x² + 4x + 6 - 6

  = \frac{2}{3} x² + 4x  ← in standard form

7 0
3 years ago
Mount Belinda is the highest point in the South Sandwich Islands, with a peak of 1,370 meters above sea level. The South Sandwic
AveGali [126]

Question is not complete. Complete question is;

Mount Belinda is the highest point in the South Sandwich Islands, with a peak at about 1,370 meters above sea level. The South Sandwich Trench, which lies about 100 kilometers (62 miles) to the east of the South Sandwich Islands, is about 8,428 meters below sea level (at its lowest point).

Part A: What is the difference in elevations between Mount Belinda and the South Sandwich Trench?

Part B: Is the elevation halfway between the peak of Mount Belinda and the South Sandwich Trench above sea level or below sea level? Give your explanation without calculating the exact value.

Part C: What elevation is halfway between the peak Mount Belinda and the South Sandwich Trench?  

Answer:

A) 100478.86 metres

B) Explained below.

C) 50239.43 metres

Step-by-step explanation:

I have attached an image showing the elevations as depicted in the question.

MB represents peak of Mount Belinda while SS represents lowest point of South Sandwich Islands.

A) Now, total vertical distance from peak of MB to lowest point of SS is;

8428 + 1370 = 9798 metres

Since the horizontal distance between MB and SS is 100000 metres, then we can use pythagoras theorem to find the Elevation between MB and SS.

If the Elevation is x.

Thus;

x = √(9798² + 100000²)

x = 100478.86 metres

B) The Elevation between peak of MB and lowest point of SS will be halfway below the sea level because the distance from the lowest point of SS from the sea level is 5 times bigger than the distance from peak of MB to the sea level.

C) The halfway Elevation between peak MB and lowest SS will be;

100478.86/2 = 50239.43 metres

3 0
3 years ago
Please anybody help me please this is so hard that not even I can't solve this I don't pay attention in class
Alla [95]

Answer:

m\angle B=54^{\circ}

m\angle BAD=36^{\circ}

m\angle CDA=90^{\circ}

BAC=72^{\circ}

Step-by-step explanation:

Given:

\overline{AB}\cong \overline{AC},

\overline{AD} bisects angle BAC

m\angle C=54^{\circ}

Triangle ABC is isosceles triangle, because \overline{AB}\cong \overline{AC}. Angles adjacent to the base of isosceles triangle ABC are congruent.

Hence,

m\angle C=m\angle B=54^{\circ}

The sum of the measures of all interior angles is 180°, so,

m\angle B+m\angle C+m\angle BAC=180^{\circ}\\ \\m\angle BAC=180^{\circ}-2\cdot 54^{\circ}=72^{\circ}

Since \overline{AD} bisects angle BAC, angles BAD and CAD are congruent by definition of angle bisector. So,

m\angle BAD=m\angle CAD=\dfrac{1}{2}m\angle BAC=\dfrac{1}{2}\cdot 72^{\circ}=36^{\circ}

AD ia angle bisector in isosceles triangle drawn to the base, so it is the height. Thus, AD and BC are perpendicular. So,

m\angle CDA=90^{\circ}

8 0
3 years ago
Which of the following represents the eccentricity of a ellipse
Gnesinka [82]

The eccentricity of an eclipse is found by using the formula, eccentricity = c/a

Where,
c represents the distance between the center and a focus.
a represent the distance between that focus and a vertex

 

The numerical value of the eccentricity of an eclipse ranges between 0 and 1

6 0
3 years ago
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