Question

Dont mind what I have wrote​

Answer 1

Answer:

n = 10

Step-by-step explanation:

$\dfrac{4^8}{(4^2)^{-3}}\div4^4=4^n\qquad\text{use}\ (a^n)^m=a^{nm}\\\\\dfrac{4^8}{4^{(2)(-3)}}}\div4^4=4^n\\\\\dfrac{4^8}{4^{-6}}\div4^4=4^n\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\4^{8-(-6)}\div4^4=4^n\\\\4^{14}\div4^4=4^n\qquad\text{use}\ a^n\div a^m=a^{n-m}\\\\4^{14-4}=4^n\\\\4^{10}=4^n\Rightarrow n=10$

Answer 2

Answer:

n = 10

Step-by-step explanation:

$\dfrac{4^8}{(4^2)^{-3}} \div 4^4 = 4^n$

$\dfrac{4^8}{4^{-6}} \div 4^4 = 4^n$

$4^8 \times 4^6 \div 4^4 = 4^n$

$4^{(8 + 6 - 4)}= 4^n$

$4^{10}= 4^n$

$n = 10$