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HACTEHA [7]
3 years ago
5

Find m∠X. Need soon THX

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

off of 3890

Step-by-step explanation:

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How to reduce 10/4 i don’t know how to
vredina [299]

answer: 10/4 reduced is 2.5/1 or 2.5.

work: what we are doing is trying to divide ten into groups of four. how many times does 10 fit into four? well, look at the multiples of four, 4, 8, 12... we can see that 8 fits into ten, but 12 doesn't. that means two whole fours can fit into ten (since 4 x 2 = 8) so we still have a  2 left over from the ten. since 2 is one half of four, we can fit in another .5. so, ten can be fit into 2.5 groups. hope this helps, have a great day!


3 0
3 years ago
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Tan42 = 7 divided by x. what is the value of x?
Tems11 [23]

Answer:

x=6

Step-by-step explanation:

42/7=6

6*7=42

42/6=7

So, works in all ways.

Hope this helps!

3 0
4 years ago
What is the negation of the follwoing conditional statement? "If a parallelogram has four congruent sides then it is a rhombus".
Kamila [148]
Negation...means put " not " in both the hypothesis and conclusion

if a parallelogram DOES NOT have 4 congruent sides, then it is NOT a rhombus.
3 0
4 years ago
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A rain jacket that usually costs r dollars is available at a discount. Drag and drop two
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4 0
3 years ago
I am currently working on Trigonometry, but unfortunately I am having a hard time. Here are some of my questions I've answered s
Novosadov [1.4K]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}\\\\
-------------------------------\\\\
cos(\theta)=\cfrac{\sqrt{3}}{3}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}
\\\\\\
\textit{using the pythagorean theorem}\implies c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b
\\\\\\
\pm\sqrt{3^2-(\sqrt{3})^2}=b\implies \pm\sqrt{6}=b

now the root gives us the +/-, which is it? well, we know the sine is negative, so the "b" value must be negative, so it has to be -√6 = b

thus  \bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(\theta)=-\cfrac{\sqrt{6}}{3}
3 0
3 years ago
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