Question

Pyramid A has a square base with side lengths of 6 meters, and 4 triangular sides with a base of 6 meters and height of 7 meters. Pyramid B has a rectangular base with length of 6 meters and height of 4 meters, and 4 triangular sides. 2 triangular sides have a base of 6 meters and height of 9 meters. The other 2 triangular sides have a base of 4 meters and height of 9.3 meters. Which pyramid has the greatest surface area? Pyramid

Answer 1

Step-by-step explanation:

6 times 9 is 54.

54 divided by 2 is 27 volume ( recipitor) is 27 for no.1

6 times 7 is 42

42 divided by 2 is 21 is the recipitor or volume for no.2

there fore a has a bigger base surface

as base is measured by recipitorial angles

sorry if this isnt the right answer or what u wanted but I know it this way

Answer 2

Answer:

Pyramid A has greater surface area

Step-by-step explanation:

Pyramid A

A=lw+l√((w /2)²+h²)+w√((l /2)²+h²)

l=w= 6 m

h= √7²-3³= √40 ≈ 6.33 m

A≈ 120 m²

Pyramid B

A=lw+l√((w /2)²+h²)+w√((l /2)²+h²)

l= 6 m

w=4 m

h= √9²-2³= √73 ≈8.54 m

A≈ 112.83 m²