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Lina20 [59]
2 years ago
11

PLEASE HELP ME QUICKKK, FIRST CORRECT PERSON GETS BRAINLIEST​

Mathematics
1 answer:
givi [52]2 years ago
8 0

Answer:

Tennessee

Step-by-step explanation:

First, let's find out how much tax he paid...

$695.49-$649.99=$45.50

We can use this to set up an equation...

x%(649.99)=45.50

We can convert x% to x/100 since any percentage is just that number over one hundred...

\frac{x}{100}*649.99=45.50\\\\\frac{649.99x}{100}=45.50

Multiply 100 to both sides

649.99x=4550

Divide both sides by 649.99

x$\approx$6.92

This is closest to 7 (our answers is not exact since you can only have two decimal places in money), therefore he lives in D. Tennessee

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480

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3 years ago
Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
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Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0
3 years ago
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