3 years ago

Can someone help with this question please?

Mathematics

1 answer:

givi [52]3 years ago

5 0

The answer which i calculated is suppose to be 13182ax

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If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the

Aleks [24]

OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13

4 0

3 years ago

If both the length and width of a rectangle are doubled, how is the area of the rectangle changed?

Law Incorporation [45]

Answer:

B) The area is four times larger

Step-by-step explanation:

$A=LW$