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tatuchka [14]
3 years ago
8

#3 PLEASE!!!! BRAINLIEST ANSWER!!! Solve the equation!! 12(3x+4)-5(2x-6)=6x-22

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

12(3x+4)-5(2x-6)=6x-22

36x + 48 - 10x + 30 = 6x - 22

26x + 48 + 30 = 6x - 22

26x + 70 = 6x - 22

20x + 70 = -22

20x = -92

x = -4.6

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Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

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Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

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Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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