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3 years ago

10

How do I find the answer to this problume−9−13+2+13minus, 9, minus, 13, plus, 2, plus, 13.

2 answers:

Whitepunk [10]3 years ago

4 0

Answer:

Answer: 12

Step-by-step explanation:

Tom [10]3 years ago

4 0

Answer:

12

Step-by-step explanation:

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Evaluate the square root to find the rational equivalent.

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3 years ago

Whats the gamble formula

Juli2301 [7.4K]

$\quad\quad\quad\quad\huge\tt{Answer \: ☕}$

┈──────────────────────────┈

<h3>The formula looks like this: </h3>

(Probability of Winning) x (Amount Won per Bet) – (Probability of Winning) x

(Amount Won per Bet) – (Probability of Losing) x (Amount Lost per Bet).

So, in our example we would plug in these variables, a 50% chance of winning, winning $6, a 50% chance of losing, and $5 lost.

<h3>The formula for expected value = </h3>

(fair win probability) x (profit if win) - (fair loss probability) x (stake).

This is the formula in the OddsJam sports betting expected value calculator.

$\LARGE \tt{Example: \color{purple}{ Amount \: of \: Win}}$

┈──────────────────────────┈

$\quad\quad\quad \large\tt{Solve \: for \: \color{red}{Amount \: of \: Win}}$

$\quad\quad \quad\quad \large\tt{x = Amount \: of \: Win}$

_ _ _ _ _ _ _ _ _ _ _ _

$\quad\quad\quad \implies\sf{0 = \frac{2}{3} * \times - .50}$

$\quad\quad\quad\implies\tt{0 + .50 = \frac{2}{3}* \times - .50 + .50 }$

$\quad\quad\quad\implies\tt{0 + .50 = \frac{2}{3} * \times + 0}$

$\quad\quad\quad\implies \color{blue}\boxed{ \tt \color{red}{.50 = \frac{2}{3}* \times }}$

_ _ _ _ _ _ _ _ _ _ _ _

Therefore, the amount of win is $\tt{.50 = \frac{2}{3}* \times }$

$\large\tt{From: \: \#Brainly.PH}$

┈──────────────────────────┈

4 0

2 years ago

The value of y varies directly with x, when y = 36, and x = 9. What is the equation for the relationship?

trapecia [35]

Answer:

4x = y

Step-by-step explanation:

If y is 36 and x is 9, you know 9 x 4 = 36. So it would be 4x = y

8 0

3 years ago

Read 2 more answers

You receive a report that to demand for lawn care services (demand) will grow from $900,000 per year to $990,000 and the availa

storchak [24]

Answer: The answer is supply.

Step-by-step explanation:

I just took the test for it.

5 0

3 years ago

Read 2 more answers

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago