Answer:
We have function,

Standard Form of Sinusoid is

Which corresponds to

where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get

Also remeber a and b is always positive
So now let answer the questions.
a. The period is


So the period is pi radians.
b. Amplitude is

Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.





So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.


Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
Answer:
y = 6
x = 0.2
Step-by-step explanation:
5x + y =7
20x + 2 = y
5x(4) + y(4) = 7(4)
20x + 4y = 28
(20x = 28 - 4y) = (20x = y - 2)
28 - 4y = y - 2
30 - 4y = y
30 = 5y
y = 6
5x + y =7
20x + 2 = y
y = 7 - 5x
7 - 5x = 20x + 2
5 - 5x = 20x
5 = 25x
x = 0.2
Answer:
x = 2
y = -3
z = 4
( 2 , -3, 4 )
Step-by-step explanation:
x + y + z = 3 ---- i
x – y =5 ---- ii
y - z = -7 ---- iii
ii + iii
x - z = -2 ---- iv
i + ii
2x + z = 8 --- v
iv + v
3x = 6
x = 2
x=2 substitute for v
z = 4
x =2 substitute for ii
y = -3
Answer:
Given system of equations:

To solve by substitution, equate the equations and solve for x:

Therefore, the x-values of the solution are
and
.
To find the y-values of the solution, substitute the found values of x into the functions:




Therefore, the solutions to the given system of equations are:
and 
If you want to multiply the two functions, the answer is a.
In fact, you have
