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kakasveta [241]
3 years ago
5

A gardener has 27 pansies and 36 daisies. he plants an equal number of each type of flower in each row. what is the greatest pos

sible number of pansi
es in each row?
Mathematics
1 answer:
VikaD [51]3 years ago
7 0
I just did this is our math book at school, but what you do is find the GCF of the numbers. So list all there factors. 27=1x27, 3x9, and that's it. 36=1x36, 2x18, 3x12, 4x9, and that's it. So, next you see that highest numbers they both have in common, in this case it is 9. So your answer is, 9 pansies.
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nordsb [41]

Answer:

We conclude that the constant of dilation is: 4

Step-by-step explanation:

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

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  • If the scale factor is between 0 and 1, it gets shrunk
  • If the scale factor = 1, the object and the image are congruent

The coordinates of the image point can be determined by multiplying the coordinates of the original point by a certain scale factor.

Given the point A'(12, 4) is the image of A(3, 1).

It is clear that the image point A'(12, 4) is enlarged 4 times of the original point A(3, 1).

It means the image point A'(12, 4) is determined when the original point A(3, 1) is dilated by a scale factor of 4.

i.e.

A(3, 1) → A'(4(3), 4(1)) → A' (12, 4)

Therefore, the rule of dilation by a scale factor 4 is:

P(x, y) → P'(4x, 4y)

Hence, we conclude that the constant of dilation is: 4

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Sonbull [250]
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A collection of coins consists of nickels, dimes, and quarters. There are
iragen [17]

Answer:

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Step-by-step explanation:

We are given relations between the number of each kind of coin and the number of quarters. So, it is convenient to write an equation in terms of the number of quarters.

Let q represent the number of quarters. The number of nickels is 3 more than that, so is (q+3). The number of dimes is 6 more than the number of quarters, so is (q+6). The total value of the coins, in cents, is ...

  5(q +3) +10(q +6) +25q = 315

  40q +75 = 315 . . . . . . . . . . . . . . collect terms

  40q = 240 . . . . . . . . . subtract 75

  q = 6 . . . . . . . . . divide by 40

  q +3 = 9 . . . . number of nickels

  q +6 = 12 . . . number of dimes

There are 9 nickels, 12 dimes, and 6 quarters in the collection.

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Neporo4naja [7]

Answer:

Step-by-step explanation:

X }

X+1 }

X+2 }

All of it has to equal 39

Add all the x’a

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