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GrogVix [38]
3 years ago
10

Thank you to whoever helps

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0
The answer is C because x2 is a parabola
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kodGreya [7K]
The answer is ERROR i tried it by hand and by calculator and both answers ended up as ERROR 
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<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Match the input values on the left ( X ) with the output values on the right ( Y ). y = 2 x + 7 1 . 9 3 2 . 13 4 3 . 15 1 4 . 11
KIM [24]

Answer:

wow let me try

Step-by-step explanation:it is a 90% sure

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3 years ago
Find the roots x^2-13x+30=0<br> (numbers only)
Morgarella [4.7K]

Answer:

Find the roots of x^2-13x+30=0 by solving for x

x= 10,3

Step-by-step explanation:

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3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Readme [11.4K]

Answer:

3/11

Step-by-step explanation:

Divide both the numerator and denominator by 2.

\dfrac{6}{22}=\dfrac{2*3}{2*11}=\dfrac{3}{11}

8 0
3 years ago
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