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Gnoma [55]
3 years ago
5

A friend has a 85% average before the final exam for a course. That score includes everything but the final, which counts for 15

% of the course grade. What is the best course grade your friend can earn?
Mathematics
2 answers:
Arlecino [84]3 years ago
7 0

Answer:

87.25%

Step-by-step explanation:

Data given in the question

Before the final exam for a course, the average percentage is 85%

The counting percentage of the course grade is 15%

So by considering the above information, the best course grade your friend is

= Average\ percentage\times remaining\ percentage + percentage\ value\times counting\ percentage= 0.85\times 0.85 + 100\%\times  0.15

= 0.7225 + 15

= 87.25%

The remaining percentage is come from

= 100% - 15%

= 85%

Hence, the best course grade is 87.25%

Svetllana [295]3 years ago
7 0

Answer:

Best course grade that can be earned = 87.25%

Step-by-step explanation:

Let the total number of marks of the exam be = 100

Exam portion conducted until now is except 15% , it means  remaining 85% test has been conducted & evaluated

  • Test Conducted, Evaluated : 85% of 100 = (85 / 100) x 100 → = 85

Score out of conducted (85% test) is 85%  : 85% of 85

= [ 85 / 100 ] x 85 → 72.25

  • Test Remaining : 15% of 100 = 15

Maximum score attainable out of 15 = 15

  • Hence : Best earn-able grade =

Grade earned out of 85% test done + Best grade attainable out of remaining 15% test

= 72.25 +15 = 87.5

Best earn-able grade in percentage = (Marks obtained / Total Marks)x 100

= ( 87.5 / 100 )  → = 87.25 %

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Answer:

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Step-by-step explanation:

We need to first find the distance between the x's.

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。☆✼★ ━━━━━━━━━━━━━━  ☾  

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