Any other time I would answer this sorry
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Answer:
The answer is "
"
Step-by-step explanation:
Distance
midpoint height 
let
Gradient 
Perpendicular Gradient
midpoints 
Similar to perpendicular
Now I'll obtain the perpendicular bisector solution
An equation of the center circle
radius will be.
Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:
20^2=12^2+x^2
400=144+x^2
x^2=400-144
x^2=256
x=16
C: B:
3 0
6 9
9 18
12 27
All you had to do was plug in the value for c or b and solve. You can tell this is most likely correct because you see patterns for both variables. C is going up by threes, while b is going up by nines.
