Any other time I would answer this sorry
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Answer:
The answer is "
"
Step-by-step explanation:
Distance
midpoint height
let
Gradient
Perpendicular Gradient
midpoints
Similar to perpendicular
Now I'll obtain the perpendicular bisector solution
An equation of the center circle
radius will be
.
Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:
20^2=12^2+x^2
400=144+x^2
x^2=400-144
x^2=256
x=16
C: B:
3 0
6 9
9 18
12 27
All you had to do was plug in the value for c or b and solve. You can tell this is most likely correct because you see patterns for both variables. C is going up by threes, while b is going up by nines.