Answer:

Step-by-step explanation:
The question relates to dividing a fraction by proper and another fraction
The given expression is presented as follows;

We rearrange the fractions as improper fractions for easier division as follows;


Therefore, we have;


Answer:
Algebra
Step-by-step explanation:
Answer:
they r all the same shap but that is all I know
The second option square root of 2^5