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Irina-Kira [14]
3 years ago
8

The length of a sticky note measures 77 mm express this length in meters

Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0
If a sticky note measures 77mm then when converted into meters it is 0.077
mr Goodwill [35]3 years ago
4 0
77mm=

Move the decimal to the left three places

77mm= .077
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Find the stated lengths in each parallelogram
alexandr1967 [171]

Answer:

40/3, 172/3, respectively

Step-by-step explanation:

x + 9 = 2y

2x = 2y + 2

x + 9 = 2(2x - 2)

4x - 4 = x + 9

3x - 13 = 0

x = 13/3

y = 40/6

RT = 13/3 + 9 = 40/3

QS = 160/3 + 4 = 172/3

8 0
3 years ago
The Cooking Club made some pies to sell
Sergio [31]

Answer:

36

Step-by-step explanation:

divide the 72 pieces by 2, you already know that 6 + 6 is 12, and 30 +30 is 60, so add 60 and 12 and you get 72

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2 years ago
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Which of the following is x=-5 a solution ?
Katarina [22]

Answer:

C and D

Step-by-step explanation:

Plug X in and see which equations/expressions are true

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3 years ago
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You order fourteen burritos to go from a Mexican restaurant, six with hot peppers and eight without. However, the restaurant for
Genrish500 [490]

Answer:

0.578

Step-by-step explanation:

If you pick three burritos at random, find the probability of the given event. (Round your answer to three decimal places.)

Given that there are 14 orders at the ratio by of:

6 with hot peppers

8 without hot peppers

At most two have hot peppers.

Binomial Problem with n = 3 ; p(hot) = 6/8

P(0<= x <=2) = 1 - P(x = 3)

= 1 - (6/8)^3

= 1 - ( 3/4 )^3

= 1 - ( 27/64 )^3

= 1- (37/64)

= 1 - 0.421875

= 0.578125

= 0.578

6 0
4 years ago
Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate
kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality x^{2}-5x+4\leq 0. To do that, factorize, then we have that (x-4)(x-1)\leq 0. This implies that

x-1\leq 0\, \text{and}\, x-4\geq 0

or

x-1 \geq 0\, \text{and}\, x-4\leq 0

In the first case the solution is the empty set \emptyset. In the second case the solution is the interval 1\leq x \leq 4. Now we have that

A=[1,4]

B=(3,5)

C=(3,4].

To show that A\cap B\subseteq C consider x\in A\cap B. Then 1\leq x \leq 4\, \text{and}\, 1, this implies that 3, then x\in C. Now, to show that C\subseteq A\cap B consider x\in C, then 3, then 1\leq x \leq 4\, \text{and}\, 3, then x\in [1,4] \, \text{and}\, x\in (3,5), this implies that x\in A\cap B.

Observe the image below.

7 0
4 years ago
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