<span>56, 90, 146, 210,</span>....i think................im so sorry if im wrong........BUT hope this helps...............have awesome day!!
Ab=81, a=81/b
s=a+b using a from above in this we get:
s(b)=81/b +b
s(b)=(81+b^2)/b
ds/db=(2b*b-81-b^2)/b^2
ds/db=(2b^2-81-b^2)/b^2
ds/db=(b^2-81)/b^2
d2s/db2=(2b^3-2b^3+81)/b^4
d2s/db2=81/b^4 since b is positive we know that the acceleration is positive so that when ds/db=0 it is a minimum for s(b)
ds/db=0 only when b^2-81=0, b^2=81, b=9
The two positive numbers are 9 and 9.
Y = kx
k = y/x = 63/14 = 4.5
so
y = 4.5(28) = 126
answer
<span>y = 126 when x = 28.</span>
In order to factor this, we will need to take something out to get it to factor. Lets take out a greatest common factor, in this case our greatest common factor will be 3.
We will then write it as:
-3(5t+2)
Answer:
Plato: C. 1040X, original return, and any supporting forms.