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2 years ago

Find the image of (-2, 1) obtained by

1 answer:

4 0

The y-axis runs vertically, so changing the y-coordinate moves a figure up or down. Adding a number to the y-coordinate shifts the image up, while subtracting a number shifts the figure down.

So to translate 3 units down, we just subtract 3 from the y-coordinate.

Instead of (-2, 1) it's now (-2, -2) since 1 - 3 (units) = -2

Now, another way to say "reflect across the y-axis" is to say "reflect across the line x=0" since the line created by graphing x=0 is the same as the y-axis.

An image that is a reflection across the y-axis, or across the line x=0, will have opposite x-coordinates from the pre-image but identical y-coordinates.

Therefore, the rule for reflecting an image across the y-axis can be described as (x, y) → (−x, y).

So using our translated point (-2, -2) it now becomes (2, -2).

You didn't provide an image, however, all you need to find is the translated and reflected point that lies on (2, -2).

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Wendy is arranging books on the bookshelves in the school library. The total number of books she arranges is given by the equati

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1
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2 years ago

Which line segment is a chord of J in the diagram below?

masha68 [24]

B

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3 years ago

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2 years ago

Read 2 more answers

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago

Can someone explain to me taxes?

jeka94

$taxes$
According to the oxford dictionary, the word taxes defines as a compulsory contribution to state revenue, levied by the government on workers' income and business profits, or added to the cost of some goods, services, and transactions.

$explanation$
Money is taken from your yearly earnings to pay for services such as the Police, Emergancy Services, Military, Schools, Postal Service ect. It is also used to pay workers who work in a federal agency such as Postal Workers and the FBI. Citizens of the United States are taxed on items that are non-edible, such as a TV, and phones in stores. Tax percentages differ in every state.

Taxes are destributed to states so the states could build roads, schools, police stations and a lot more stuff.

The country can run Social Programs such as Social Security from taxes.

5 0

3 years ago