$\bf \begin{array}{cllll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-7&5^{-7}\to \frac{1}{5^7}\to \frac{1}{78125}\\\\
-3&5^{-3}\to \frac{1}{5^3}\to \frac{1}{125}\\\\
0&5^0\to 1\\\\
3&5^3\to 125\\\\
7&5^7\to 78125
\end{array}$

so... you can keep on going towards the negatives with "x", or towards the positives with "x", notice, if the "x" is negative, "y" is just a fraction, positive, but a fraction

and if "x" is positive, "y" is a positive integer
even when x =0, "y" never became 0, and is never negative either

so, the range is, "y" is always positive, but not 0, or y>0

6 0

4 years ago

What is the digit in the ten billions place in this number 30,242,386,651

Minchanka [31]

It’s 1 that’s in the ten billions

8 0

4 years ago

Researchers collected a simple random sample of the times that 81 college students required to earn their bachelor’s degrees. Th

damaskus [11]

Answer:

0.4459

Step-by-step explanation:

Let the random age variable, X = 4.5; mean,∪ = 4.8; standard deviation, α = 2.2

By comparing P ( 0≤ Z ≤ 4,8)

P(Z ≤ X - ∪/α) = P(Z ≤ 4.5 - 4.8/2.2) = P(Z ≤ - 0.136)

Using the table: P(0≤ Z ≤ 1) = 0.0541

P(Z > 1) = (0.5 - 0.0541) = 0.4459

∴ P(Z > 4.5) = 0.4459

3 0

3 years ago