<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
Answer:
This is an exponential function
Step-by-step explanation:
f(x)=2(3)^x is one example of the exponential function. Since f(0) = 2(1) = 2, the y-intercept is (0, 2). The x-axis is the horizontal asymptote. The graph begins in Quadrant II, passes through (0, 2) and continues to increase, faster and faster, in Quadrant I. Next time, please be more specific about what you'd like to know.
Answer:
7 fiction and 23 non- fiction
Step-by-step explanation:
The number of non-fiction read was 5 less than 4 times the number of fiction books.
Assume fiction books are x.
An equation representing this would be:
x + (4x - 5) = 30
5x - 5 = 30
5x = 30 + 5
x = 35 / 5
x = 7 fiction books
Non-fiction books:
= 4x - 5
= 4 * 7 - 5
= 23 non - fiction books
X=1, y=-2--------------------------
