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3 years ago

What is the simplified form of x plus 1 over x squared plus x minus 6 divided by x squared plus 5x plus 4 over x plus 3 ?

2 answers:

6 0

X² + x - 6 = x² + 3 x - 2 x - 6 = x ( x + 3 ) - 2 ( x + 3 ) = ( x + 3 ) ( x - 2 )
x² + 5 x + 4 = x² + x + 4 x + 4 = x ( x + 1 ) + 4 ( x + 1 ) = ( x + 1 ) ( x + 4 )
( x + 1 ) / ( x² + x - 6 ) : ( x² + 5 x + 4 ) / ( x + 3 ) =
= ( x + 1 ) / ( x² + x + 6 ) · ( x + 3 ) / ( x² + 5 x + 4 ) =
= ( x + 1 ) / ( x + 3 ) ( x - 2 ) · ( x + 3 ) / ( x + 1 ) ( x + 4 ) =
= 1 / ( x - 2)( x + 4 )

Jobisdone [24]3 years ago

3 0

Answer:

1 / (x + 3) (x - 2)

Step-by-step explanation:

This is the correct answer i just took the test!

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A projector was sold after allowing 10% discount on the marked price and levying 13% VAT .If the selling price of the projector

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The marked price of the projector is $50,000.

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The price of the projector after the discount can be represented with:

(100 - 10%)x - 90%x = 0.90x

Where x is the marked price

The price of the projector after the VAT is : (1.13) x 0.90x = 1.02x

Difference in price = 1.02x - 0.90x = 5850

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x = 5850 / 0.12

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1 year ago

25 Points!!!!!!!!!!!!!!!!!!

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No it is not 25 it 13 points why would you lie to me

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2 years ago

Edison Research gathered exit poll results from several sources for the Wisconsin recall election of Scott Walker. They found th

olchik [2.2K]

Answer: Our required probability is 0.515.

Step-by-step explanation:

Since we have given that

Probability that the respondents voted in favor of Scot Walker P(F) = 56%

Probability that the respondent voted in not favor of Scot Walker = 100-56 = P(F')=44%

Probability of those who did vote in favor had a college degree = 36% = P(C|F)

Probability of those who did vote against had a college degree = 44% = P(C|F')

So, we will use "Conditional Probability":

probability that he voted in favor of Scott Walker given that they had a college degree is given by

$P(F|C)=\dfrac{0.56\times 0.36}{0.56\times 0.36+0.44\times 0.43}\\\\P(F|C)=0.515$

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3 years ago

Which table represents a quadratic relationship?

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In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

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Dmitriy789 [7]

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