Answer:
use photomath and your welcome :)))
I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.
Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b. Now, it's shortened to be 56ab2-35.
Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.
I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.
So, that means the answer is 56ab2-35.
I hope this helps!! (And makes sense)
Answer
I joined but it said it was full
We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.
We know that area of rectangle is width times length.
To find the area of the given rectangle we will multiply both side lengths as:
Therefore, the area of the given rectangle would be 
square yards.
A)
<h3>
The sample mean is 52</h3><h3>
The claimed population mean is 44</h3>
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The sample mean is the mean found in the survey (of the sample of people). The sample mean is found by adding up the values and dividing by the sample size n. The larger n gets, the closer the sample mean should get to the population mean. This is assuming the sample is random and representative of the population.
The population mean is a claim made by another study/survey/etc. Usually generalized statements such as "Americans spent an average of X dollars (in year Y)" would have X be considered the population mean.
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B)
<h3>Sample mean is 3.42</h3><h3>Claimed population mean is 3.56</h3>
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Same idea as part A, but we're using different numbers and a different problem context.
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Note: The year numbers and the sample sizes are not used to answer any of the four questions above.
