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3 years ago

2. What number am I?

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

Answer:

i have no clue sorry..... you can delete this btw

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Describe the explicit formula?

lukranit [14]

Answer:

its to a power so it is an exponential power

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3 years ago

Raziel walks 3 m north, 5 m east, 3 m south, and 5 m west. What is the total distance Raziel traveled? (Include

blsea [12.9K]

Answer:

16 metres

Step-by-step explanation:

You're finding the perimetre of this rectangle, so have to add each side together to find the total distance he traveled (the perimetre of the rectangle, since he travelled in a rectangle).

3*2 is 6,

5*2 is 10

10 + 6 is 16.

Have a wonderful day, my friend.

4 0

3 years ago

What expression represents the product of 3 less than twice x and 2 more than the quantity 3 times x?

Georgia [21]

"3 less than twice 'x' " . . . . that's (2x - 3)

" 2 more than the quantity (3 x) " . . . . . that's (3x + 2)

Their product is
(2x - 3) (3x + 2) .

If you want to expand it to a single expression, perform the multiplication,
and you have
6x² - 5x - 6 .

8 0

3 years ago

Can someone please help me figure out how to do this problem. We have tried several different ways and none of them come up as b

Ilya [14]

Answer:

Step-by-step explanation:

Order of operations: PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

5(9)+2(6) ÷ 3 + $5^{2}$

= 45+12÷ 3 +25

=45+4+25

=74

8 0

3 years ago

Read 2 more answers

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

3 years ago