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Fed [463]
3 years ago
13

Express the edge length of a cube as a function of the cube's diagonal length d. Then express the surface area & volume of t

he cube as a function of the diagonal length.
Mathematics
2 answers:
Lorico [155]3 years ago
8 0
D = sqrt(3s^2) where s is the length of the side. Solving for s, 

<span>3s^2 = d^2 iff </span>
<span>s^2 = d^2 / 3 iff </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) or d sqrt(3) / 3 </span>

<span>Surface area of the cube = 6 s^2. Thus, </span>
<span>A = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>

<span>Volume = s^3. Thus, </span>
<span>V = (d / sqrt(3))^3 </span>
<span>= d^3 / 3sqrt(3) </span>
<span>= d^3 sqrt(3) / 9</span>
IgorLugansk [536]3 years ago
8 0
D = sqrt(3s^2) , 

<span>3s^2 = d^2 </span>
<span>s^2 = d^2 / 3 </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) </span>
now we will find surface area 
therefore
<span>Surface area of the cube = 6 s^2.</span>
<span>Area  = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>
now we shall find volume 
<span>V = s^3.</span>
<span>V = (d / sqrt(3))^3 </span>
<span>= d^3 / 3sqrt(3) </span>
<span>= d^3 sqrt(3) /9
hope this helps</span>
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