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Grace [21]
3 years ago
5

Which of the following equations describes the line shown below? check all that apply

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0
The equation of the line can be written as:

y - 3 =  2( x + 2) 
and
y - 9 = 2(x - 1)

So the answers are  E and F

Hope this helps :)
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What is 30,000 expressed in scientific notation?
OlgaM077 [116]

The answer is b. It is the only choice that equals the right answer. You could also write this as 3 * 10^4, which is equivalent to b.

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3 years ago
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Please help i will give 5 stars
NeTakaya
1. C = 10π; A = 25π
2. 254.34
3. 12
4. without a picture it is just a shot 390 mm3
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A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

8 0
3 years ago
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Complete the net worth statement by determining the total assets and total liabilities. What is the net worth?
MArishka [77]

Answer:

B

Step-by-step explanation:

1. Add all of the assets($12,700) and all of the liabilities($10,700).

2. Subtract the liabilities from the assets.

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3 years ago
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Solve.
Eva8 [605]

2x^2+x-1=2\ \ \ |-2\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\ \ |-3\\2x=-3\ \ \ |:2\\x=-\frac{3}{2}\\\\x-1=0\ \ \ |+1\\x=1

Answer: C 1, -3/2

4 0
3 years ago
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