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g100num [7]
2 years ago
9

The line AB is shown on the grid.

Mathematics
1 answer:
Aleksandr [31]2 years ago
6 0

a) The gradient of a line perpendicular to AB is -2.

b) equation of line is y=-2x+6

<h3>What is gradient?</h3>

The gradient is the measure of the steepness of a straight line.

a)The gradient of line is

=(-2-2)/(7+1)

=-4/8

=-1/2

So, gradient of a line perpendicular to AB is  -2

b)The coordinates of mid point (3, 0)

m = -2

So,

0= -6+ b

b= 6

So, equation of line is y=-2x+6

Learn more about this concept here:

brainly.com/question/19465597

#SPJ1

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Setler [38]

Answer:

The answer is option A.

The first graph

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3 years ago
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Evaluate:<br><br> 16 - 12 + 13.5 - - 14
Oxana [17]

Answer:

31.5

Step-by-step explanation:

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Vincent is ordering accessories for his surfboard. A set of fins cost $24 each and a leash costs $15. The shipping cost is $4 pe
Hitman42 [59]

Answer:

Here, b represents buying fins and leashes.

As per the statement:

Vincent is ordering accessories for his surfboard. A set of fins cost $24 each and a leash costs $15.

A set of fins cost $24 each and a leash costs $15

⇒ Cost of total fins = 24 b and Cost of total leashes = 15 b

It is also given that: The shipping cost is $4 per order.

then;

Cost in dollars of buying b fins and b leashes plus the cost of shipping

= 24b+15b+4

Therefore, the expression  24b+15b+4 represents the cost in dollars of buying b fins and b leashes plus the cost of shipping.

10

(a)

True.

The given terms in the expressions are 24b, 10b and 4

(b)

True.

Like terms are those which have same variable.

Like terms in the given expression are: 24 b and 15 b

(c)

False.

Combine like terms in the given expression:

 39b+4

Therefore, the simplified given expression is,   39b+4

7 0
3 years ago
Find the circumference of a circle with a diameter of 20 inches.
Elena-2011 [213]

62.8319 in

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3 years ago
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Find the exponential function P(t)=P0a^t where P(2)=5 and P(4)=10
asambeis [7]

Answer:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

Step-by-step explanation:

P(2)=5 meants when t=2, that the value for P(t) is 5.

So this gives us this equation:

5=P_0 \cdot a^2

P(4)=10 meants when t=4, that the value for P(t) is 10.

So this gives us this equation:

10=P_0 \cdot a^4

So I take equation 2 and divide it be equation 1 I get:

\frac{10}{5}=\frac{P_0 \cdot a_4}{P_0 \cdot a_2}

Simplifying:

2=a^2

Since the base for an exponential function can't be negative then a=\sqrt{2}.

So plugging into one of my equations I began with gives me an equation to solve for the initial value,P_0:

5=P_0 \cdot (\sqrt{2})^2

5=P_0 \cdot 2

Divide both sides by 2:

\frac{5}{2}=P_0

The function is:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

7 0
3 years ago
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