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Stolb23 [73]
2 years ago
7

A small ball floats on the surface of the water in a wave pool. As a wave moves past the ball, the ball's

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0

Answer:

The correct option is;

d(t) = 6·cos(π/3·t) + 28

Step-by-step explanation:

The general form of a cosine function is given as follows;

y = A·cos(B·x - C) + D

Where;

A = The amplitude = The distance from the peak to the midline = 1/2×(Maximum - minimum)

The amplitude = 1/2 × (34 - 22) = 6 inches

B = 2·π/P = 2·π/6 = π/3

P = The period = 6 seconds

C/B = The phase shift

D = The midline = Minimum  + Amplitude = 22 + 6 = 28 inches

x = The independent variable

Therefore, to model the function of the wave can be given as follows;

d(t) = 6·cos(π/3·t) + 28

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Complete the slope-intercept form of the linear equation that represents the relationship in the table.
Mrac [35]

The equation of the line that passes through points (-1, -10), and (3, 14) is y = 6x - 4.

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A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

We have two points shown in the table:

(-1, -10), and (3, 14)

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Learn more about the slope of the straight line here:

brainly.com/question/3493733

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