3 years ago

Allen found 28 pieces of gold Diana found 1880558 pieces of gold how many pieces of gold did they have total

Mathematics

2 answers:

horsena [70]3 years ago

4 0

Well, you need to add 28 to 1880558 which equals 1,880,586.

Irina-Kira [14]3 years ago

4 0

Add 28 and 1880558 which is equal to 1880586.

You might be interested in

Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1

lana [24]

Answer:

3 &4

Step-by-step explanation:

7 0

2 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$