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strojnjashka [21]
3 years ago
7

A wildflower bouquet costs $4.25 at the farmer's market. A vase can be purchased for an additional $3.50. Kelly has $20 to buy a

bouquet for her mother with a vase. She'd also like to buy just a bouquet for herself and another for her best friend.
If x represents the number of bouquets Kelly can buy, which inequality will tell Kelly if she has enough money to make her purchase?
A) $4.25x + $3.50 ≤ $20
B) $4.25x - $3.50 ≤ $20
Eliminate
C) $4.25x + $3.50 ≥ $20
D) $3.50x + $4.25 ≤ $20;
Mathematics
2 answers:
natulia [17]3 years ago
7 0
The answer is A you need to multiply the number of buquets then add it to thr price of the vase
Jobisdone [24]3 years ago
4 0
A you need to multiply and add and honestly you could use a calculator to solve this
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The reference angle for an angle whose measure is 260° is
Maurinko [17]
So, 260 degrees is in the 3rd quadrant, only 10 degrees away from being straight down at 270 degrees....if you have a xy axis, and draw a line segment from the origin into the 3rd quadrant, then at the endpoint of that segment, draw back up to the x-axis, your reference angle is the angle that the line segment makes with the x-axis (in this case, the negative portion of the x-axis), which is 80 degrees....since 260 degrees is 80 degrees past 180.

So your answer is 80 degrees.

Hope this helps,

Brian
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%20%5Cdiv%20153%20%3D%20" id="TexFormula1" title="3 \div 153 = " alt="3 \div 153 = " align="a
beks73 [17]

If you're looking for the simplified version of the fraction, you have to factor both numerator and denominator.

The numerator is actually already a prime number, so we're good

The denominator factors as 153 = 3^2\cdot 17

So, a 3 appears in both numerator and denominator. We can simplify it:

\cfrac{3}{153} = \cfrac{3}{3^2\cdot 17} = \cfrac{1}{3\cdot 17} = \cfrac{1}{51}

If you want to compute the approximated value of this fraction, simply plug these values into some calculator to get

\cfrac{1}{51} \approx 0.0196078431372\ldots

5 0
3 years ago
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Two cyclists start from 98 miles apart and begin racing toward each
kati45 [8]

The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

Let the speed of one bicyclist=x mph

Let the speed of the other bicyclist=(x+3) mph

Hence:

Speed of one bicyclist:

3x+3(x+3)+2=98

3x+3x+9+2=98

6x=87

Divide both side by 6x

x=87/6

x=14.5 mph

Speed of the other bicyclist:

x+3 mph

14.5 mph+3 mph

=17.5 mph

Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

Learn more here:

brainly.com/question/18839894

3 0
2 years ago
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A cannon ball is launched at 6 feet per second from the top of a platform 12 feet above the ground.
AleksAgata [21]
A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12

b.) The y-intercept is 12

c.) The y-intercept represent the height of the ball at time t = 0

d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
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The sum of two numbers is 21 the second number is six times the first number.work out the two numbers
kiruha [24]

Answer: First number 3 Second 18

Step-by-step explanation:

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